Integrand size = 24, antiderivative size = 20 \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=-\frac {x}{a}+\frac {\tan (c+d x)}{a d} \]
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Time = 0.05 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3250, 3254, 3852, 8} \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=\frac {\tan (c+d x)}{a d}-\frac {x}{a} \]
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Rule 8
Rule 3250
Rule 3254
Rule 3852
Rubi steps \begin{align*} \text {integral}& = -\frac {x}{a}+\int \frac {1}{a-a \sin ^2(c+d x)} \, dx \\ & = -\frac {x}{a}+\frac {\int \sec ^2(c+d x) \, dx}{a} \\ & = -\frac {x}{a}-\frac {\text {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{a d} \\ & = -\frac {x}{a}+\frac {\tan (c+d x)}{a d} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.35 \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=\frac {-\frac {\arctan (\tan (c+d x))}{d}+\frac {\tan (c+d x)}{d}}{a} \]
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Time = 0.40 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.20
method | result | size |
derivativedivides | \(\frac {\tan \left (d x +c \right )-\arctan \left (\tan \left (d x +c \right )\right )}{d a}\) | \(24\) |
default | \(\frac {\tan \left (d x +c \right )-\arctan \left (\tan \left (d x +c \right )\right )}{d a}\) | \(24\) |
risch | \(-\frac {x}{a}+\frac {2 i}{d a \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}\) | \(30\) |
parallelrisch | \(\frac {-\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) x d +d x -2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d a \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}\) | \(53\) |
norman | \(\frac {\frac {x}{a}+\frac {x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}-\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d a}-\frac {4 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {2 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}-\frac {x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2} \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}\) | \(143\) |
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Time = 0.26 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.70 \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=-\frac {d x \cos \left (d x + c\right ) - \sin \left (d x + c\right )}{a d \cos \left (d x + c\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 100 vs. \(2 (12) = 24\).
Time = 0.92 (sec) , antiderivative size = 100, normalized size of antiderivative = 5.00 \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=\begin {cases} - \frac {d x \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{a d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} - a d} + \frac {d x}{a d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} - a d} - \frac {2 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{a d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} - a d} & \text {for}\: d \neq 0 \\\frac {x \sin ^{2}{\left (c \right )}}{- a \sin ^{2}{\left (c \right )} + a} & \text {otherwise} \end {cases} \]
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Time = 0.36 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.30 \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=-\frac {\frac {d x + c}{a} - \frac {\tan \left (d x + c\right )}{a}}{d} \]
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Time = 0.30 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.30 \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=-\frac {\frac {d x + c}{a} - \frac {\tan \left (d x + c\right )}{a}}{d} \]
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Time = 13.75 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.00 \[ \int \frac {\sin ^2(c+d x)}{a-a \sin ^2(c+d x)} \, dx=\frac {\mathrm {tan}\left (c+d\,x\right )}{a\,d}-\frac {x}{a} \]
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